x^2+16x+96=5

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Solution for x^2+16x+96=5 equation: 



x^2+16x+96=5

We move all terms to the left:

x^2+16x+96-(5)=0

We add all the numbers together, and all the variables

x^2+16x+91=0

a = 1; b = 16; c = +91;
Δ = b2-4ac
Δ = 162-4·1·91
Δ = -108
Delta is less than zero, so there is no solution for the equation

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